http://comparecamerasales.com/lens-physics-equations/
Physics Question?
I’m having some difficulty with this lens/image question, so any guidance for part B of this question that anyone can give me would be much appreciated. Here’s the problem:
A slide projector has a converging lens whose focal length is 104.00 mm.
(a) How far (in meters) from the lens must the screen be located if a slide is placed 108.70 mm from the lens?
2.405m (answer i obtained using the thin lens equation)
(b) If the slide measures 24.0 mm x 36.0 mm, what are the dimensions (in mm) of its image?
_____mm x ______ mm
-I attempted to solve this by using the magnification equation. m= (-Distance of image)/(distance of object)= (-2.405m)/.1087m but the answer I got of -22.125m (converted to -22125 millimeters) led to some very large answers that were incorrect when i used this number to multiply each dimension of the slide by, so I’m pretty sure I’m missing something. Can anyone help?
Your numbers look right to me.
magnification = (-2.405m)/.1087m = -22.125
(Note that magnification, being distance/distance is a pure number – 22.125, not 22.125 meters.)
image height = slide height x magnification = 22.125 x 24.0 mm = 531 mm = 0.531 meters (about 21 inches)
Physics: optics of lenses and mirrors (8)
|
|
The Ray and Wave Theory of Lenses (Cambridge Studies in Modern Optics) $119.94 This book describes techniques used to predict the quality of images formed by optical systems, such as telescopes, camera lenses, and microscope objectives. It covers in detail how the ray and wave pictures of lens behavior can be combined and developed to produce a theory capable of dealing with the large angles encountered in real optical systems. Several applications are considered, including … |
